You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0‘s.
Increment the large integer by one and return the resulting array of digits.
Example 1:
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Input: digits = [1,2,3] Output: [1,2,4] Explanation: The array represents the integer 123. Incrementing by one gives 123 + 1 = 124. Thus, the result should be [1,2,4].
Example 2:
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Input: digits = [4,3,2,1] Output: [4,3,2,2] Explanation: The array represents the integer 4321. Incrementing by one gives 4321 + 1 = 4322. Thus, the result should be [4,3,2,2].
Example 3:
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Input: digits = [9] Output: [1,0] Explanation: The array represents the integer 9. Incrementing by one gives 9 + 1 = 10. Thus, the result should be [1,0].
My Answer
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var plusOne = function(digits) { const digitsLen = digits.length const lastDigit = digits[digitsLen - 1] if (lastDigit !== 9) return [...digits.slice(0, digitsLen - 1), lastDigit + 1] let index = digitsLen - 1 do { index -- } while(digits[index] === 9) const prefix = index < 0 ? [] : digits.slice(0, index) const addedNum = index >= 0 ? digits[index] + 1 : 1 return prefix.concat(addedNum).concat(newArray(digitsLen - index - 1).fill(0)) };