LeetCode 算法题【Easy】：7. Reverse Integer

链接：https://leetcode.com/problems/reverse-integer/

Question

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Example 3:

Input: x = 120
Output: 21

Constraints:

• 231 <= x <= 231 - 1

My Answer

var reverse = function(x) {
    if (x === 0) return 0
    let result = 0
    if (x > 0) {
        result = Number(String(x).split('').reverse().join(''))
    } else {
        result = Number('-' + String(Math.abs(x)).split('').reverse().join(''))
    }
    if (result > Math.pow(2, 31) || result < Math.pow(2, 31) * -1) return 0
    return result
};

My Answer’s Performance